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Question

A car moving at 50m/s decelerates uniformly to rest over 125m. What is the time taken to stop?

Options

Choose one · Correct answer highlighted

Explanation

Use v2=v02+2ax to find a: 0=(50)2+2a(125)⇒0=2500+250a⇒a=−10m/s2. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 5 s as the result, so option D is correct.