Skip to content
Login Register

#compression

11 public questions tagged with this topic.

Stress, Strain and Hooke's Law

A water sample of volume 3litres is compressed by a pressure of 4×106N/m2. If the bulk modulus of water is 2.2×109N/m2,

Bulk modulus: B = −pΔVV. Rearrange: ΔVV = −pB = −4×1062.2×109≈−1.82×10−3. Volume: V = 3litres = 3×10−3m3. Change in volume: ΔV = ΔVV×V = −1.82×10−3×3×10−3≈−5.45×10−6m3. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 5.45×10−6m3. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.

View Details
Stress, Strain and Hooke's Law

A water sample of volume 1.5litres is compressed by a pressure of 3×106N/m2. If the bulk modulus of water is 2.2×109N/m2

Bulk modulus: B = −pΔVV. Rearrange: ΔVV = −pB = −3×1062.2×109≈−1.36×10−3. Volume: V = 1.5litres = 1.5×10−3m3. Change in volume: ΔV = ΔVV×V = −1.36×10−3×1.5×10−3≈−2.04×10−6m3. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2.04×10−6m3. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.

View Details
Bulk Modulus and Compressibility

An aluminium rod of length 1.4m and cross-sectional area 2×10−6m2 is compressed by a force producing a stress of 3×107N/

Young's modulus: Y = StressStrain. Strain: Strain = StressY = 3×1077×1010≈4.29×10−4. Compression: ΔL = Strain×L = 4.29×10−4×1.4≈6×10−4m = 0.6mm. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 0.6mm. This satisfies dimensional consistency and physical conditions given, so option D is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

View Details
Stress, Strain and Hooke's Law

An aluminium rod of length 1.6m and cross-sectional area 2×10−6m2 is compressed by a force of 600N. If the Young's modul

Young's modulus: Y = FLAΔL. Rearrange: ΔL = FLAY. Substitute: ΔL = 600×1.62×10−6×7×1010 = 9601.4×105≈6.86×10−3m = 6.86mm. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 6.86mm. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

View Details
Laws of Motion and Energy Conservation

A 8kg mass falls from 5m onto a spring (k\=2500N/m). What is the maximum compression? (Take g\=10m/s2)

Potential energy mgh=8×10×5=400J. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 400 J. This satisfies dimensional consistency and physical conditions given, so option A is scientifically correct.

Ref: NCERT Class 11 Physics > Chapter 6: Work, Energy and Power > Topic: Laws of Motion and Energy Conservation

View Details