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Practice question

MCQ

Question

A steel rod of length 0.8 m and cross-sectional area 2 × 10-5 m2 is compressed by a force of 800 N. If the Young's modulus of steel is 2 × 1011 N/m2, what is the compression?

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Explanation

Young's modulus: Y = (F L) / (A ΔL). Rearrange: ΔL = (F L) / (A Y). Substitute: ΔL = (800 × 0.8) / (2 × 10-5 × 2 × 1011) = 640 / (4 × 106) = 1.6 × 10-4 m = 0.16 mm.

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