Practice question
Question
A glass slab of volume 0.025m3 is subjected to a hydraulic pressure of 4×106N/m2. If the bulk modulus of glass is 3.7×1010N/m2, what is the change in volume?
Explanation
Bulk modulus: B = −pΔVV. Rearrange: ΔVV = −pB = −4×1063.7×1010≈−1.08×10−4. Change in volume: ΔV = ΔVV×V = −1.08×10−4×0.025≈−2.7×10−6m3. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2.7×10−6m3. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.