10 public questions tagged with this topic.
Bulk modulus: B = −pΔVV. Rearrange: ΔVV = −pB = −5×1063.7×1010≈−1.35×10−4. Magnitude: 1.35×10−4. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.35×10−4. This satisfies dimensional consistency and physical conditions given, so option A is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
Bulk modulus: B = −pΔVV. Rearrange: ΔVV = −pB = −5×1063.7×1010≈−1.35×10−4. Change in volume: ΔV = ΔVV×V = −1.35×10−4×0.03≈−4.05×10−6m3. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 4.05×10−6m3. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
Bulk modulus: B = −pΔVV. Rearrange: ΔVV = −pB = −7×1063.7×1010≈−1.89×10−4. Magnitude: 1.89×10−4. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.89×10−4. This satisfies dimensional consistency and physical conditions given, so option A is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
Bulk modulus: B = −pΔVV. Rearrange: ΔVV = −pB = −4×1063.7×1010≈−1.08×10−4. Change in volume: ΔV = ΔVV×V = −1.08×10−4×0.025≈−2.7×10−6m3. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2.7×10−6m3. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
Bulk modulus: B = −pΔVV. Rearrange: ΔVV = −pB = −2×1063.7×1010≈−5.41×10−5. Change in volume: ΔV = ΔVV×V = −5.41×10−5×0.01≈−5.41×10−7m3. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 5.41×10−7m3. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
Bulk modulus: B = -p / (ΔV / V). Rearrange: ΔV / V = -p / B. Substitute: ΔV / V = -(8 × 106) / (3.7 × 1010) ≈ -2.16 × 10-4. Magnitude: 2.16 × 10-4.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
Bulk modulus: B = −pΔVV. Rearrange: ΔVV = −pB = −8×1063.7×1010≈−2.16×10−4. Magnitude: 2.16×10−4. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2.16×10−4. This satisfies dimensional consistency and physical conditions given, so option A is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
Bulk modulus: B = −pΔVV. Rearrange: ΔVV = −pB = −6×1063.7×1010≈−1.62×10−4. Magnitude: 1.62×10−4. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.62×10−4. This satisfies dimensional consistency and physical conditions given, so option A is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
Bulk modulus: B = -p / (ΔV / V). Rearrange: ΔV / V = -p / B. Substitute: ΔV / V = -(1 × 107) / (7.2 × 1010) ≈ -1.39 × 10-4. Magnitude: 1.39 × 10-4.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
Bulk modulus: B = −pΔVV. Rearrange: ΔVV = −pB = −3×1063.7×1010≈−8.11×10−5. Magnitude: 8.11×10−5. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 8.11×10−5. This satisfies dimensional consistency and physical conditions given, so option D is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
