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Practice question

MCQ

Question

A steel rod of length 0.6 m and cross-sectional area 5 × 10-6 m2 is compressed by a force producing a strain of 3 × 10-4. If the Young's modulus of steel is 2 × 1011 N/m2, what is the force applied?

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Explanation

Young's modulus: Y = Stress / Strain. Stress: Stress = Y × Strain = 2 × 1011 × 3 × 10-4 = 6 × 107 N/m2. Force: F = Stress × A = 6 × 107 × 5 × 10-6 = 300 N.

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