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A primary amine like CH₃NH₂ can be dialkylated with excess CH₃CH₂Cl to form CH₃N(CH₂CH₃)₂, a tertiary amine, as per the PDF’s alkylation.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Nomenclature, Structure and Preparation - Ammonolysis and Gabriel Synthesis
Aniline (C₆H₅NH₂) can be alkylated with CH₃CH₂Cl and a base to form N-ethylaniline (C₆H₅NHCH₂CH₃), as per the PDF’s alkylation.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Nomenclature, Structure and Preparation - Ammonolysis and Gabriel Synthesis
Propan-1-amine (CH₃CH₂CH₂NH₂) reacts with CH₃CH₂Cl and a base to form N-ethylpropan-1-amine (CH₃CH₂CH₂NHCH₂CH₃), as per the PDF’s alkylation.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Nomenclature, Structure and Preparation - Ammonolysis and Gabriel Synthesis
Ethylamine (CH₃CH₂NH₂) with excess CH₃Cl undergoes alkylation to form CH₃CH₂N(CH₃)₂ (N,N-dimethylethylamine), a tertiary amine, as per the PDF.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Nomenclature, Structure and Preparation - Ammonolysis and Gabriel Synthesis
Ethylamine (CH₃CH₂NH₂) with excess CH₃Cl forms N,N-dimethylethylamine (CH₃CH₂N(CH₃)₂), a tertiary amine, as per the PDF’s alkylation.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Nomenclature, Structure and Preparation - Ammonolysis and Gabriel Synthesis
A secondary amine like CH₃NHCH₃ reacts with CH₃CH₂Cl to add an ethyl group, forming a tertiary amine (CH₃CH₂N(CH₃)₂), as per the PDF’s alkylation.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Nomenclature, Structure and Preparation - Ammonolysis and Gabriel Synthesis
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