Practice question
Question
The product of C₆H₅NH₂ reacting with CH₃CH₂Cl in the presence of a base is:
Explanation
Aniline (C₆H₅NH₂) can be alkylated with CH₃CH₂Cl and a base to form N-ethylaniline (C₆H₅NHCH₂CH₃), as per the PDF’s alkylation.
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