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Question

What is the product when CH₃CH₂NHCH₂CH₃ reacts with excess CH₃I followed by NaOH ?

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Explanation

N-Ethylethanamine with excess CH₃I forms a quaternary salt ( CH₃CH₂N(CH₃)2CH₂CH₃+I- ), which with NaOH yields CH₃CH₂N(CH₃)CH₂CH₃ via elimination. This follows from NCERT principle where relation explains outcome clearly for students.

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