Practice question
Question
What is the product when CH₃CH₂NHCH₂CH₃ reacts with excess CH₃I followed by NaOH ?
Explanation
N-Ethylethanamine with excess CH₃I forms a quaternary salt ( CH₃CH₂N(CH₃)2CH₂CH₃+I- ), which with NaOH yields CH₃CH₂N(CH₃)CH₂CH₃ via elimination. This follows from NCERT principle where relation explains outcome clearly for students.
Discussion
Comments
Please log in to join the discussion.
Login to commentNo comments yet. Be the first to start the discussion.