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Question

The standard enthalpy of formation of NH₃(g) is -46.1 kJ/mol. What is Δ H for N₂(g) + 3H₂(g) → 2NH₃(g)?

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Explanation

Δ H = 2 × Δ Hf° (NH₃) - [Δ Hf° (N₂) + 3 × Δ Hf° (H₂)] = 2 × (-46.1) - [0 + 0] = -92.2 kJ/mol.

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