Practice question
Question
A train moving at 90km/h accelerates at 0.8m/s2 for 15s, then decelerates at 2.5m/s2 to rest. What is the total distance covered?
Explanation
Speed: 90km/h=25m/s. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 730 m as the result, so option A is correct.
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