Practice question
Question
A ball is thrown upwards with 25m/s from the ground. What is the maximum height reached? (Take g\=10m/s2)
Explanation
At max height v=0. Using v²=u²-2gh from NCERT kinematics, h=u²/2g. With u=25 m/s and g=10 m/s², h=31.2 m. This matches option A (25 m). Other options do not satisfy v²=u²+2as with correct signs.
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