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Question

A ball is thrown at 35m/s at 37∘. What is its time of flight? (Take g\=10m/s2,sin⁡37∘\=0.6)

Options

Choose one · Correct answer highlighted

Explanation

Time of flight Tf=2v0sin⁡θ0g. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 3 s as the result, so option A is correct.