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Practice question

MCQ

Question

A particle starts from rest with a constant acceleration of (6i^−4j^)m/s2. What is its speed after 2s?

Options

Choose one · Correct answer highlighted

Explanation

Velocity v=v0+at, with v0=0. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 14.42 m/s as the result, so option A is correct.

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