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#particle motion

8 public questions tagged with this topic.

A particle starts with velocity 5i^m/s and accelerates at (−3j^)m/s2. What is its displacement magnitude after 2s?

Displacement r=v0t+12at2. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 10 m as the result, so option A is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Acceleration and Velocity Analysis - Part 8

A particle’s position is given by x\=5t−3t2 and y\=4t2 (in meters and seconds). What is its speed at t\=1s?

Velocity: vx=dxdt=5−6t,vy=dydt=8t. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 5 m/s as the result, so option A is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Straight Line Motion - Mixed Concepts

A particle’s position is given by x\=5t−t2 and y\=2t2 (in meters and seconds). What is the magnitude of its acceleration

Velocity: vx=dxdt=5−2t,vy=dydt=4t. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 2 m/s² as the result, so option A is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Straight Line Motion - Mixed Concepts

A particle moves at 18m/s and decelerates at 4m/s2 for 2s, then accelerates at 3m/s2 until its speed is 18m/s. What is t

Phase 1: v=18−4⋅2=10m/s, x1=18⋅2−12⋅4⋅(2)2=36−8=28m. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 65 m as the result, so option A is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Distance, Displacement and Velocity-Time Relations