Practice question
Question
A 4kg particle moves with velocity v\=−2j^m/s at r\=5i^m. What is the magnitude of its angular momentum about the origin?
Explanation
L = r×p = |i^j^k^5000−20| = k^(5×(−2)−0×0) = −10k^kg m2/s. Magnitude = 10kg m2/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 10 kg m²/s. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
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