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#distance calculation

14 public questions tagged with this topic.

Rotational Motion Applications

Two particles of masses 4kg and 6kg are at (2,0) and (0,3) respectively. What is the distance of their center of mass fr

X = (4×2)+(6×0)4+6 = 810 = 0.8. Y = (4×0)+(6×3)4+6 = 1810 = 1.8. Distance = (0.8)2+(1.8)2 = 0.64+3.24 = 3.88≈1.97m. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.97 m. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

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Rotational Motion Applications

Two particles of masses 2kg and 8kg are at (1,5) and (4,1) respectively. What is the distance of their center of mass fr

X = (2×1)+(8×4)2+8 = 2+3210 = 3.4. Y = (2×5)+(8×1)2+8 = 10+810 = 1.8. Distance = (3.4)2+(1.8)2 = 11.56+3.24 = 14.8≈3.85m. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 3.85 m. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

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Conservation of Angular Momentum

Two particles of masses 6kg and 4kg are at (2,3) and (8,7) respectively. What is the distance of their center of mass fr

X = (6×2)+(4×8)6+4 = 12+3210 = 4.4. Y = (6×3)+(4×7)6+4 = 18+2810 = 4.6. Distance = (4.4)2+(4.6)2 = 19.36+21.16 = 40.52≈6.36m. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 6.36 m. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

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Center of Mass and System of Particles

Two particles of masses 7kg and 3kg are at (0,6) and (5,0) respectively. What is the distance of their center of mass fr

X = (7×0)+(3×5)7+3 = 1510 = 1.5. Y = (7×6)+(3×0)7+3 = 4210 = 4.2. Distance = (1.5)2+(4.2)2 = 2.25+17.64 = 19.89≈4.46m. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 4.46 m. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

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Equations of Motion and Problem Solving

A train moving at 90km/h accelerates at 0.8m/s2 for 15s, then decelerates at 2.5m/s2 to rest. What is the total distance

Speed: 90km/h=25m/s. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 730 m as the result, so option A is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Equations of Motion and Problem Solving

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Equations of Motion and Problem Solving

A rocket accelerates from rest at 4m/s2 for 6s, then moves at constant speed for 5s. What is the total distance covered?

Phase 1: v=4⋅6=24m/s, x1=12⋅4⋅(6)2=72m. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 192 m as the result, so option D is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Equations of Motion and Problem Solving

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Distance, Displacement and Velocity-Time Relations

A cyclist moves at a constant speed of 12m/s for 30s. What is the distance covered?

For constant speed, distance x=vt. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 360 m as the result, so option D is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Distance, Displacement and Velocity-Time Relations

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Distance, Displacement and Velocity-Time Relations

A car moving at 27m/s decelerates uniformly to rest in 9s. What is the distance covered?

Find a=v−v0t=0−279=−3m/s2. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 100 m as the result, so option A is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Distance, Displacement and Velocity-Time Relations

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