Practice question
Question
A metal has a threshold wavelength of 500 nm. What is the stopping potential when irradiated with light of wavelength 400 nm? (h = 6.626 × 10⁻³⁴ J s, c = 3.0 × 10⁸ m s⁻¹, e = 1.6 × 10⁻¹⁹ C)
Explanation
W₀ = hc/λ₀ ≈ 3.976×10⁻¹⁹ J. E = hc/λ ≈ 4.970×10⁻¹⁹ J. KE ≈ 9.94×10⁻²⁰ J. Vₛ = KE/e ≈ 0.621 V.
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