25 public questions tagged with this topic.
T₂ = T₁ (V₁/V₂)γ⁻¹ = 300 × (18/6)⁰.³³ = 300 × 3⁰.³³ = 300 × 1.44 = 432 K.
Ref: NCERT Class 11 Chemistry > Chapter 5: Thermodynamics > Topic: Third Law of Thermodynamics and Applications
For irreversible expansion against constant pext, w = -pext Δ V, where Δ V is the volume change.
Ref: NCERT Class 11 Chemistry > Chapter 5: Thermodynamics > Topic: Gibbs Energy and Gibbs Energy Change and Equilibrium
E ≈ 5.301×10⁻¹⁹ J. KE ≈ 8.008×10⁻²⁰ J.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Shapes of Orbitals - s p d f and Nodes and Radial Probability
The Balmer series lies in the visible region.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Shapes of Orbitals - s p d f and Nodes and Radial Probability
ΔE = 108.8 eV. λ ≈ 11.42 nm.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Shapes of Orbitals - s p d f and Nodes and Radial Probability
λ = h/(mv) = 6.65×10⁻¹⁰ m.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Quantum Mechanical Model - de Broglie Heisenberg and Schrodinger
n=4 to n=2. λ = 486.1 nm.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Quantum Mechanical Model - de Broglie Heisenberg and Schrodinger
vₑ/v_α = m_α/mₑ ≈ 7297.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Quantum Mechanical Model - de Broglie Heisenberg and Schrodinger
For l=2 (d subshell), orbitals = 5. Electrons = 5×2 = 10.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Quantum Mechanical Model - de Broglie Heisenberg and Schrodinger
mₚ vₚ = m_α v_α. vₚ/v_α = m_α/mₚ ≈ 4.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Quantum Mechanical Model - de Broglie Heisenberg and Schrodinger
W₀ = hc/λ₀ ≈ 3.976×10⁻¹⁹ J. E = hc/λ ≈ 4.970×10⁻¹⁹ J. KE ≈ 9.94×10⁻²⁰ J. Vₛ = KE/e ≈ 0.621 V.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Quantum Mechanical Model - de Broglie Heisenberg and Schrodinger
v = h/(mλ) = 2.645×10⁵ m s⁻¹. KE = ½mv² = 5.837×10⁻¹⁷ J.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Quantum Mechanical Model - de Broglie Heisenberg and Schrodinger
