A metal has a threshold wavelength of 500 nm. What is the stopping potential when irradiated with light of wavelength 40
W₀ = hc/λ₀ ≈ 3.976×10⁻¹⁹ J. E = hc/λ ≈ 4.970×10⁻¹⁹ J. KE ≈ 9.94×10⁻²⁰ J. Vₛ = KE/e ≈ 0.621 V.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Quantum Mechanical Model - de Broglie Heisenberg and Schrodinger