Practice question
Question
A dry cell delivers 0.25 A for 9650 s. How many grams of zinc are oxidized at the anode? (Atomic mass of Zn = 65 g/mol, F = 96500 C/mol)
Explanation
Charge = 0.25 × 9650 = 2412.5 C . Zn → Zn²⁺ + 2e⁻ , 1 mol Zn (65 g) requires 2F. Faradays = (2412.5/96500) = 0.025 F , Moles = (0.025/2) = 0.0125 mol , Mass = 0.0125 × 65 = 0.8125 g .
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