228 public questions tagged with this topic.
Reaction: Oâ‚‚ + 4H+ + 4e- -> 2Hâ‚‚O . 4 electrons per mole of Oâ‚‚. This follows from NCERT principle where the relation explains the outcome clearly for students in simple steps.
Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom and Periodicity, Topic: Mole concept, atomic models and periodic trends.
Given: How many Faradays of electricity are required to deposit 0.635 g of copper from CuSO₄ solution? (Molar mass of Cu = 63.5 g/mol) These values define the system as per NCERT data. Formula: Moles of Cu = 0.635/63.5 = 0.01 mol. This is standard NCERT relation. Substitution & Calculation: Reaction: Cu²⁺ + 2e⁻ → Cu(s), 2F deposits 63.5 g. . Faradays = 0.01 × 2 = 0.02 F . Result: The computed value matches expected outcome and confirms correct choice as per NCERT.
Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom, Periodicity and relevant Chemistry topic, Topic: Mole concept and periodic trends.
Given: What is the ll constant if the resistance of a conductivity ll with 0.01 M KCl solution is 200 Ω and its conductivity is 0.14 × 10â»Â² S cmâ»Â¹? These values define the system as per NCERT data. Formula: Cell constant, G^* = kappa × R = 0.14 × 10â»Â² × 200 = 0.28 cm^{-1 .. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Substituting values like 1.2 × 10â»âµ, 236 J kgâ»Â¹ Kâ»Â¹, CH₃CHâ‚‚NHâ‚‚ etc. into the formula and simplifying step by step. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Solutions, Topic: Concentration terms and colligative properties.
Given: What is the potential of a hydrogen electrode in a solution with pH = 5 at 298 K, given E⁰ = 0 V ? Formula: For H+ + e- -> 1/2 H₂, E = E⁰ - 0.059/1 log frac1[H^+]. Substitution & Calculation: [H^+] = 10⁻⁵, E = 0 - 0.059 × 5 = -0.295 V . Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.
Ref: NCERT Chemistry Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII)Topic: Mole concept, atomic structure, chemical formulas like H₂O, CO₂, CH₃CH₂NH₂ and periodic trends.
Given: What is the EMF of a ll with Zn(s) | Zn²âº(0.05 M) || Hâº(0.1 M) | Hâ‚‚(g, 1 bar) | Pt(s) at 298 K, given E_{Zn^{2+/Znâ° = -0.76 V and E_{H^{+/H_2â° = 0 V ? These values define the system as per NCERT data. Formula: E_{llâ° = 0 - (-0.76) = 0.76 V, n = 2. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: E_{ll = E_{llâ° - 0.059/2 log frac[Zn^{2+][H^{+]² . Q = 0.05/(0.1)² = 5, log Q = 0.699 . E_{ll = 0.76 - 0.059/2 × 0.699 = 0.76 - 0.0206 = 0.7394 V approx 0.74 V . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Relevant Chemistry topic covering principles and examples as per NCERT.
Given: What is the mass of nickel deposited at the cathode when a 5 A current flows through Ni(NO₃)â‚‚ solution for 20 minutes? (Molar mass of Ni = 58.7 g/mol, F = 96500 C/mol) These values define the system as per NCERT data. Formula: Q = 5 × 1200 = 6000 C. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: For Ni²⺠+ 2e⻠→ Ni(s), 2F (193000 C) deposits 58.7 g. Mass = 58.7 × 6000/193000 approx 1.824 g . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Solutions, Topic: Concentration terms and colligative properties.
Given: What is the EMF of a ll with Ni(s) | Ni²⁺(0.005 M) || Ag⁺(0.001 M) | Ag(s) at 298 K, given E_{Ni^{2+/Ni⁰ = -0.25 V and E_{Ag^{+/Ag⁰ = 0.80 V ? These values define the system as per NCERT data. Formula: E_{ll⁰ = 0.80 - (-0.25) = 1.05 V, n = 2. This is standard NCERT relation. Substitution & Calculation: E_{ll = E_{ll⁰ - 0.059/2 log frac[Ni^{2+][Ag^{+]² . Q = 0.005/(0.001)² = 5000, log Q = 3.699 . E_{ll = 1.05 - 0.059/2 × 3.699 = 1.05 - 0.109 = 0.941 V approx 0.94 V . Result: The computed value matches expected outcome and confirms correct choice as per NCERT.
Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom, Periodicity and relevant Chemistry topic, Topic: Mole concept and periodic trends.
Given: How much current (in amperes) is required to deposit 0.159 g of copper from CuSO₄ solution in 482.5 seconds? (Molar mass of Cu = 63.5 g/mol, F = 96500 C/mol) Formula: Moles of Cu = 0.159/63.5 = 0.0025 mol. Substitution & Calculation: Reaction: Cu²⁺ + 2e⁻ → Cu(s), 2F deposits 63.5 g. . Charge = 0.0025 × 2 × 96500 = 482.5 C . Current = Q/t = 482.5/482.5 = 1 A . Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.
Ref: NCERT Chemistry Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII), Chapter: Electrochemistry (Latest NCERT 2026-27), Topic: Faraday's laws, charge required to reduce Al³⁺, 3F = 3 × 96500 C
Given: What is the standard electrode potential of a galvanic ll where zinc is oxidized and copper is reduced, given their standard reduction potentials are -0.76 V and 0.34 V respectively? These values define the system as per NCERT data. Formula: Standard ll potential, E_{ll⁰ = E_{cathode⁰ - E_{anode⁰. This is standard NCERT relation. Substitution & Calculation: For Zn(s) → Zn²⁺(aq) + 2e⁻ (anode) and Cu²⁺(aq) + 2e⁻ → Cu(s) (cathode): E_{ll⁰ = 0.34 - (-0.76) = 1.10 V . Result: The computed value matches expected outcome and confirms correct choice as per NCERT.
Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom, Periodicity and relevant Chemistry topic, Topic: Mole concept and periodic trends.
Given: What is the ll potential at 298 K for Ni(s) + 2Ag⁺(0.002 M) → Ni²⁺(0.160 M) + 2Ag(s) if E_{ll⁰ = 1.05 V ? These values define the system as per NCERT data. Formula: E_{ll = E_{ll⁰ - 0.059/2 log frac[Ni^{2+][Ag^{+]². This is standard NCERT relation. Substitution & Calculation: Q = 0.160/(0.002)² = 40000, log Q = 4.602 . E_{ll = 1.05 - 0.059/2 × 4.602 = 1.05 - 0.136 = 0.914 V approx 0.91 V . Result: The computed value matches expected outcome and confirms correct choice as per NCERT.
Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom, Periodicity and relevant Chemistry topic, Topic: Mole concept and periodic trends.
Given: What is the molar conductivity at infinite dilution for NaCl if the ionic molar conductivities of Na⺠and Clâ» are 50.1 S cm² molâ»Â¹ and 76.3 S cm² molâ»Â¹ respectively? These values define the system as per NCERT data. Formula: Kohlrausch’s law: Lambda_mâ° = lambda_{Na^{+â° + lambda_{Cl^{-â°. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Lambda_mâ° = 50.1 + 76.3 = 126.4 S cm² mol^{-1 . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Relevant Chemistry topic covering principles and examples as per NCERT.
Given: What is the equilibrium constant for the reaction Fe(s) + 2Ag⁺(aq) → Fe²⁺(aq) + 2Ag(s) if E_{ll⁰ = 1.24 V at 298 K? Formula: E_{ll⁰ = 0.059/n log K_c, n = 2. Substitution & Calculation: 1.24 = 0.059/2 log K_c, log K_c = 1.24 × 2/0.059 = 42.03 . K_c = __10POW₄₂__.03 approx 1.07 × __10POW₄₂__. Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.
Ref: NCERT Chemistry Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII)Topic: Mole concept, atomic structure, chemical formulas like H₂O, CO₂, CH₃CH₂NH₂ and periodic trends.
