Practice question
Question
What is the emf of the cell Cr(s) | Cr³⁺(0.001 M) || Cu²⁺(0.01 M) | Cu(s) at 298 K? (Given: E°Cr³⁺/Cr = -0.74 V , E°Cu²⁺/Cu = 0.34 V )
Explanation
E°cell = 0.34 - (-0.74) = 1.08 V . Ecell = 1.08 - (0.059/6) log ((0.001)²/0.01) = 1.08 - 0.01967 = 1.06033 V .
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