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#water flow

6 public questions tagged with this topic.

Fluid Pressure, Pascal's Law and Manometers

Water (ρ\=1000kg/m3) flows horizontally at 3.5m/s with pressure 1.7×105Pa. If the speed rises to 6m/s, what is the new p

Bernoulli’s equation: P1+12ρv12 = P2+12ρv22. P1 = 1.7×105Pa, v1 = 3.5m/s, v2 = 6m/s, ρ = 1000kg/m3. P2 = 1.7×105+12×1000(12.25−36) = 1.7×105−11875 = 1.58125×105Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.58 × 10⁵ Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.

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Surface Tension, Capillarity and Excess Pressure

A pipe narrows from 0.07m2 to 0.035m2. If water flows at 2.4m/s in the wider section, what is the speed in the narrower

Continuity equation: A1v1 = A2v2. A1 = 0.07m2, v1 = 2.4m/s, A2 = 0.035m2. v2 = A1v1A2 = 0.07×2.40.035 = 4.8m/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 4.8 m/s. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

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Equation of Continuity and Flow Rate

A tank has a hole 1.3m below the water surface, open to the atmosphere. What is the efflux speed? (Take g\=9.8m/s2)

Torricelli’s law: v = 2gh. g = 9.8m/s2, h = 1.3m. v = 2×9.8×1.3 = 25.48≈5.05m/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 5.0 m/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

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Fluid Pressure, Pascal's Law and Manometers

Water flows at 3m/s at 2m height with pressure 1.3×105Pa. What is the pressure at 0m height with speed 4m/s? (ρ\=1000kg/

Bernoulli’s: P1+12ρv12+ρgh1 = P2+12ρv22+ρgh2. Left: 1.3×105+12×1000×9+1000×10×2 = 1.3×105+4500+20000 = 1.545×105. Right: P2+12×1000×16 = P2+8000. 1.545×105 = P2+8000, P2 = 1.465×105Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.465 × 10⁵ Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.

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Fluid Pressure, Pascal's Law and Manometers

Water flows at 2.0m/s at 1.5m height with pressure 1.65×105Pa. What is the pressure at 0.2m height with speed 3.0m/s? (ρ

Bernoulli’s: P1+12ρv12+ρgh1 = P2+12ρv22+ρgh2. Left: 1.65×105+12×1000×4+1000×9.8×1.5 = 1.65×105+2000+14700 = 1.817×105. Right: P2+12×1000×9+1000×9.8×0.2 = P2+4500+1960 = P2+6460. 1.817×105 = P2+6460, P2 = 1.7524×105Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.75 × 10⁵ Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.

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Fluid Pressure, Pascal's Law and Manometers

A horizontal pipe carries water (ρ\=1000kg/m3) at 2m/s and 1.4×105Pa. If the speed becomes 5m/s, what is the pressure?

Bernoulli’s equation: P1+12ρv12 = P2+12ρv22. P1 = 1.4×105Pa, v1 = 2m/s, v2 = 5m/s, ρ = 1000kg/m3. P2 = 1.4×105+12×1000(4−25) = 1.4×105−10500 = 1.295×105Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.295 × 10⁵ Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.

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