Practice question
Question
Water (ρ\=1000kg/m3) flows horizontally at 3.5m/s with pressure 1.7×105Pa. If the speed rises to 6m/s, what is the new pressure?
Explanation
Bernoulli’s equation: P1+12ρv12 = P2+12ρv22. P1 = 1.7×105Pa, v1 = 3.5m/s, v2 = 6m/s, ρ = 1000kg/m3. P2 = 1.7×105+12×1000(12.25−36) = 1.7×105−11875 = 1.58125×105Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.58 × 10⁵ Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Discussion
Comments
Share your thoughts. New comments appear after admin approval.
Please log in to join the discussion.
Login to commentNo comments yet. Be the first to start the discussion.