8 public questions tagged with this topic.
Stress: Stress = F / A. Area: A = π r2, r = 1 × 10-3 m. A = 3.14 × (1 × 10-3)2 = 3.14 × 10-6 m2. Force: F = Stress × A = 5 × 107 × 3.14 × 10-6 = 157 N.
Ref: University Physics, Chapter 17: Thermal Expansion.
Elongation: ΔL = (F L) / (A Y). Ratio: (ΔLsteel)/(ΔLcopper) = Ycopper / Ysteel = (1.1 × 1011) / (2 × 1011) = 11/20 = 0.55. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 0.55. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: University Physics, Chapter 17: Thermal Expansion.
Stress: Stress = F / A = 1000 / (1 × 10-5) = 1 × 108 N/m2. Young's modulus: Y = Stress / Strain. Strain: Strain = Stress / Y = (1 × 108) / (2 × 1011) = 5 × 10-4.
Ref: University Physics, Chapter 17: Thermal Expansion.
Stress: Stress = F / A. Area: A = π r2, r = 1 × 10-3 m. A = 3.14 × (1 × 10-3)2 = 3.14 × 10-6 m2. Force: F = Stress × A = 4 × 107 × 3.14 × 10-6 = 125.6 N.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
Stress: Stress = FA. Area: A = πr2 = 3.14×(0.01)2 = 3.14×10−4m2. Force: F = Stress×A = 4×107×3.14×10−4 = 1.256×104N. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.256×104N. This satisfies dimensional consistency and physical conditions given, so option A is scientifically correct.
Ref: University Physics, Chapter 17: Thermal Expansion.
Stress: Stress = FA. Area: A = πr2 = 3.14×(0.008)2 = 3.14×6.4×10−5≈2.01×10−4m2. Force: F = Stress×A = 5×107×2.01×10−4≈1.005×104N. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.005×104N. This satisfies dimensional consistency and physical conditions given, so option A is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
Stress: Stress = FA = 5002.5×10−6 = 2×108N/m2. Young's modulus: Y = StressStrain. Strain: Strain = StressY = 2×1081.1×1011≈1.82×10−3. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.82×10−3. This satisfies dimensional consistency and physical conditions given, so option A is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
Stress is given by: Stress = F / A. Area A = π r2, where r = (1/2) × 10-3 m = 5 × 10-4 m. So, A = 3.14 × (5 × 10-4)2 = 3.14 × 25 × 10-8 = 7.85 × 10-7 m2. Stress: 100 / (7.85 × 10-7) ≈ 1.27 × 108 N/m2.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
