Skip to content
Login Register

Practice question

MCQ

Question

A copper wire of length 1.5 m and diameter 1 mm is subjected to a tensile force of 100 N. If the Young's modulus of copper is 1.1 × 1011 N/m2, what is the stress in the wire?

Options

Choose one · Correct answer highlighted

Explanation

Stress is given by: Stress = F / A. Area A = π r2, where r = (1/2) × 10-3 m = 5 × 10-4 m. So, A = 3.14 × (5 × 10-4)2 = 3.14 × 25 × 10-8 = 7.85 × 10-7 m2. Stress: 100 / (7.85 × 10-7) ≈ 1.27 × 108 N/m2.

Related blogs

Guides and insights connected to this topic