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Practice question

MCQ

Question

A brass wire of length 1.5 m and cross-sectional area 2.5 × 10-6 m2 is stretched by a force of 150 N. If the elongation is 0.25 mm, what is the Young's modulus of brass?

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Explanation

Young's modulus: Y = (F L) / (A ΔL). Substitute: ΔL = 0.25 × 10-3 m. Y = (150 × 1.5) / (2.5 × 10-6 × 0.25 × 10-3) = 225 / (6.25 × 10-10) = 3.6 × 1011 N/m2.

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