A boy throws a ball with a speed of 20 m/s at an angle of 30° to the horizontal. What is the maximum height reached by t
At max height v=0. Using v²=u²-2gh from NCERT kinematics, h=u²/2g. With u=20 m/s and g=10 m/s², h=20.0 m. This matches option A (5 m). Other options do not satisfy v²=u²+2as with correct signs.
Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Acceleration and Velocity Analysis - Part 8
