Practice question
Question
A boy throws a ball with a speed of 20 m/s at an angle of 30° to the horizontal. What is the maximum height reached by the ball? (Take g = 10 m/s²)
Explanation
At max height v=0. Using v²=u²-2gh from NCERT kinematics, h=u²/2g. With u=20 m/s and g=10 m/s², h=20.0 m. This matches option A (5 m). Other options do not satisfy v²=u²+2as with correct signs.
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