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#projectile range

2 public questions tagged with this topic.

Motion in a Plane and Projectile Motion

A projectile is launched at 25m/s at 60∘. What is its range? (Take g\=10m/s2,sin⁡120∘\=0.866)

Projectile motion splits into horizontal uniform and vertical accelerated motion per NCERT Chapter 4. Range R=u²sin2θ/g and max height H=u²sin²θ/2g. Using given u, θ, g, calculation yields 50 m. Hence option A satisfies projectile formulas.

Ref: NCERT Class 11 Physics > Chapter 4: Motion in a Plane > Topic: Motion in a Plane and Projectile Motion

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Acceleration and Velocity Analysis

A ball is thrown at 20m/s at 45∘ from a height of 5m. What is its range? (Take g\=10m/s2)

Time of flight: y=v0yt−12gt2, where y=−5m,v0y=20sin⁡45∘=102. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 50 m as the result, so option B is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Acceleration and Velocity Analysis - Part 8

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