Skip to content
Login Register

Practice question

MCQ

Question

A projectile is launched at 25m/s at 60∘. What is its range? (Take g\=10m/s2,sin⁡120∘\=0.866)

Options

Choose one · Correct answer highlighted

Explanation

Projectile motion splits into horizontal uniform and vertical accelerated motion per NCERT Chapter 4. Range R=u²sin2θ/g and max height H=u²sin²θ/2g. Using given u, θ, g, calculation yields 50 m. Hence option A satisfies projectile formulas.

Discussion

Comments

0 comments

Share your thoughts. New comments appear after admin approval.

No comments yet. Be the first to start the discussion.

Related blogs

Guides and insights connected to this topic