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#physics numericals

21 public questions tagged with this topic.

At what depth below Earth’s surface is g reduced to 6.86m/s2? (g0\=9.8m/s2,RE\=6.4×106m)

g(d) = g0(1−d/RE). 6.86 = 9.8(1−d/RE). 1−d/RE = 0.7. d/RE = 0.3. d = 0.3×6.4×106 = 1.92×106m. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.9 × 10⁶ m. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

How much energy is required to move a 400kg satellite from 8RE to 16RE from Earth’s center? (ME\=6×1024kg,RE\=6.4×106m,G

ΔE = −GMEm(1r2−1r1). r1 = 5.12×107m, r2 = 1.024×108m. ΔE = −6.67×10−11×6×1024×400(11.024×108−15.12×107). ΔE = −1.601×1017(−9.766×10−9)≈1.56×109J. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.6 × 10⁹ J. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: Halliday & Resnick, Fundamentals of Physics, 11th ed., Chapter 13: Gravitation.

A satellite orbits a planet at 6×107m from its center with a period of 15 hours. What is the planet’s mass? (G\=6.67×10−

M = 4π2r3GT2. T = 15×3600 = 54000s, T2 = 2.916×109s2. r3 = (6×107)3 = 2.16×1023m3. M = 4×(3.14)2×2.16×10236.67×10−11×2.916×109. M = 8.51×10241.948×10−1≈4.37×1025kg. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 4.4 × 10²⁵ kg. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: Halliday & Resnick, Fundamentals of Physics, 11th ed., Chapter 13: Gravitation.

At what depth below Earth’s surface is g reduced to 7.35m/s2? (g0\=9.8m/s2,RE\=6.4×106m)

g(d) = g0(1−d/RE). 7.35 = 9.8(1−d/RE). 1−d/RE = 0.75. d/RE = 0.25. d = 0.25×6.4×106 = 1.6×106m. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.6 × 10⁶ m. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

What is the kinetic energy of a 600kg satellite at 8RE from Earth’s center? (ME\=6×1024kg,RE\=6.4×106m,G\=6.67×10−11N m2

K = GMEm2r. r = 8RE = 5.12×107m. K = 6.67×10−11×6×1024×6002×5.12×107. K = 2.401×10171.024×108≈2.34×109J. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2.4 × 10⁹ J. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: Halliday & Resnick, Fundamentals of Physics, 11th ed., Chapter 13: Gravitation.

What is the gravitational force on a 9kg mass 7m from the center of a spherical shell of mass 350kg and radius 5m? (G\=6

Outside shell: F = GMmr2. F = 6.67×10−11×350×972. F = 2.101×10−849≈4.29×10−10N. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 4.3 × 10⁻¹⁰ N. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: Halliday & Resnick, Fundamentals of Physics, 11th ed., Chapter 13: Gravitation.

Two masses 9kg and 18kg are 18m apart. What is the gravitational potential at a point 8m from the 9kg mass? (G\=6.67×10−

Distance to 18kg: 18−8 = 10m. U = −Gm1r1−Gm2r2. U = −6.67×10−11(98+1810). U = −6.67×10−11(1.125+1.8)≈−1.95×10−10J/kg. As per NCERT, applying relevant law/formula with correct units and sign convention leads to -1.9 × 10⁻¹⁰ J/kg. This satisfies dimensional consistency and physical conditions given, so option A is scientifically correct.

Ref: Halliday & Resnick, Fundamentals of Physics, 11th ed., Chapter 13: Gravitation.

A satellite’s period is 100 minutes at h\=0. What is its period at h\=2RE? (RE\=6.4×106m)

T2∝(RE+h)3. T02 = kRE3, T2 = k(3RE)3 = 27kRE3. T = T027 = 100×5.196≈520min. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 520 min. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: Halliday & Resnick, Fundamentals of Physics, 11th ed., Chapter 13: Gravitation.

What is the kinetic energy of a 400kg satellite at 6RE from Earth’s center? (ME\=6×1024kg,RE\=6.4×106m,G\=6.67×10−11N m2

K = GMEm2r. r = 6RE = 3.84×107m. K = 6.67×10−11×6×1024×4002×3.84×107. K = 1.601×10177.68×107≈2.08×109J. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2.1 × 10⁹ J. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: Halliday & Resnick, Fundamentals of Physics, 11th ed., Chapter 13: Gravitation.

What is the gravitational force on a 10kg mass outside a spherical shell of mass 500kg and radius 2m, at 3m from the cen

Outside a shell, F = GMmr2. F = 6.67×10−11×500×1032. F = 3.335×10−79≈3.71×10−8N. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 3.7 × 10⁻⁸ N. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: Halliday & Resnick, Fundamentals of Physics, 11th ed., Chapter 13: Gravitation.

What is the escape speed from a planet with mass 1.2×1024kg and radius 3×106m? (G\=6.67×10−11N m2/kg2)

ve = 2GMR. ve = 2×6.67×10−11×1.2×10243×106. ve = 5.336×107≈7.3×103m/s = 7.3km/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 7.3 km/s. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: Halliday & Resnick, Fundamentals of Physics, 11th ed., Chapter 13: Gravitation.