Practice question
Question
A satellite’s period is 100 minutes at h\=0. What is its period at h\=2RE? (RE\=6.4×106m)
Explanation
T2∝(RE+h)3. T02 = kRE3, T2 = k(3RE)3 = 27kRE3. T = T027 = 100×5.196≈520min. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 520 min. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
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