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#oxygen volume

5 public questions tagged with this topic.

During electrolysis of aqueous NiSO₄ with Ni electrodes, 0.59 g of Ni (atomic mass 59 g/mol) is deposited at the cathode

Cathode: Ni²⁺ + 2e⁻ → Ni . Moles = (0.59/59) = 0.01 mol , Charge = 0.01 × 2 × 96500 = 1930 C . Anode: 2H₂O → O₂ + 4H⁺ + 4e⁻ . 1 mol O₂ (22.4 L) requires 4F. Faradays = (1930/96500) = 0.02 F , Moles O₂ = (0.02/4) = 0.005 mol , Volume = 0.005 × 22.4 = 0.112 L .

Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Electrolytic Cells and Electrolysis and Faraday's Laws

What volume of O₂ at STP is required to burn 5.6 g of C₂H₄ completely to CO₂ and H₂O? (Molar mass: C₂H₄ = 28 g/mol)

Reaction: C₂H₄ + 3O₂ → 2CO₂ + 2H₂O. Moles of C₂H₄ = 5.6/28 = 0.2 mol. 1 mol C₂H₄ needs 3 mol O₂; 0.2 mol needs 0.6 mol. Volume = 0.6 × 22.4 = 13.44 L.

Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Reactions in Solutions and Mass Percentage and Numericals

What volume of O₂ at STP is required to burn 11 g of C₂H₆ completely to CO₂ and H₂O? (Molar mass: C₂H₆ = 30 g/mol)

Reaction: 2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O. Moles of C₂H₆ ≈ 0.3667 mol. 2 mol need 7 mol O₂; 0.3667 mol need ≈ 1.2833 mol. Volume = 1.2833 × 22.4 ≈ 28.75 L.

Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Laws of Chemical Combination - Conservation Mass Definite Multiple

What volume of O₂ at STP is required to burn 6 g of CH₄ completely to CO₂ and H₂O? (Molar mass: CH₄ = 16 g/mol)

Reaction: CH₄ + 2O₂ → CO₂ + 2H₂O. Moles of CH₄ = 6/16 = 0.375 mol. 1 mol CH₄ needs 2 mol O₂; 0.375 mol needs 0.75 mol. Volume = 0.75 × 22.4 = 16.8 L.

Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Laws of Chemical Combination - Conservation Mass Definite Multiple

What volume of O₂ at STP is required to burn 9 g of C₃H₈ completely to CO₂ and H₂O? (Molar mass: C₃H₈ = 44 g/mol)

Reaction: C₃H₈ + 5O₂ → 3CO₂ + 4H₂O. Moles of C₃H₈ ≈ 0.2045 mol. 1 mol needs 5 mol O₂; 0.2045 mol needs 1.0225 mol. Volume = 1.0225 × 22.4 ≈ 22.9 L.

Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Importance and Nature of Chemistry and Properties of Matter