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Question

What volume of O₂ at STP is required to burn 11 g of C₂H₆ completely to CO₂ and H₂O? (Molar mass: C₂H₆ = 30 g/mol)

Options

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Explanation

Reaction: 2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O. Moles of C₂H₆ ≈ 0.3667 mol. 2 mol need 7 mol O₂; 0.3667 mol need ≈ 1.2833 mol. Volume = 1.2833 × 22.4 ≈ 28.75 L.