Practice question
Question
What volume of O₂ at STP is required to burn 11 g of C₂H₆ completely to CO₂ and H₂O? (Molar mass: C₂H₆ = 30 g/mol)
Explanation
Reaction: 2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O. Moles of C₂H₆ ≈ 0.3667 mol. 2 mol need 7 mol O₂; 0.3667 mol need ≈ 1.2833 mol. Volume = 1.2833 × 22.4 ≈ 28.75 L.