3 public questions tagged with this topic.
Δ Tf = Kf · m . 0.62 = 1.86 × (moles/0.6) . Moles = (0.62 × 0.6/1.86) ≈ 0.2 . Mass = 0.2 × 62 = 12.4 g .
Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Abnormal Molar Masses and van't Hoff Factor
Reaction: Fe₂O₃ + 3CO → 2Fe + 3CO₂. Moles of Fe₂O₃ = 16/160 = 0.1 mol. 0.1 mol Fe₂O₃ produces 0.2 mol Fe = 0.2 × 56 = 11.2 g.
Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Stoichiometry and Stoichiometric Calculations and Limiting Reagent
Reaction: Fe₂O₃ + 3CO → 2Fe + 3CO₂. Moles of Fe = 16.8/56 = 0.3 mol. 2 mol Fe from 1 mol Fe₂O₃; 0.3 mol from 0.15 mol. Mass = 0.15 × 160 = 24 g.
Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Stoichiometry and Stoichiometric Calculations and Limiting Reagent
