Practice question
Question
How many grams of Fe₂O₃ are required to produce 16.8 g of Fe with excess CO? (Molar masses: Fe₂O₃ = 160 g/mol, Fe = 56 g/mol)
Explanation
Reaction: Fe₂O₃ + 3CO → 2Fe + 3CO₂. Moles of Fe = 16.8/56 = 0.3 mol. 2 mol Fe from 1 mol Fe₂O₃; 0.3 mol from 0.15 mol. Mass = 0.15 × 160 = 24 g.
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