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Total mass = 5.6 + 44.4 = 50 g. Mass % = (5.6/50) × 100 = 11.2%.
Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Stoichiometry and Stoichiometric Calculations and Limiting Reagent
Mass of 1 L solution = 1000 × 1.05 = 1050 g. Mass of KOH = 1.5 × 56 = 84 g. Mass of water = 1050 − 84 = 966 g = 0.966 kg. Molality = 1.5 / 0.966 ≈ 1.55 m.
Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Stoichiometry and Stoichiometric Calculations and Limiting Reagent
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