#Henry's law

Vapour Pressure and Raoult's Law - Ideal and Non-ideal Solutions

A gas has a Henry’s law constant of 400 bar. If its partial pressure is 8 bar, what is the mole fraction in the solution

p = KH · x . x = (8/400) = 0.02 .

Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Vapour Pressure and Raoult's Law - Ideal and Non-ideal Solutions

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Vapour Pressure and Raoult's Law - Ideal and Non-ideal Solutions

A gas has a Henry’s law constant of 350 bar at 25°C. If 0.02 mole of the gas is dissolved in 800 g of water at 7 bar, wh

Molality = (moles/mass of solvent in kg) = (0.02/0.8) = 0.025 mol/kg . Cross-check: x = (7/350) = 0.02 , slightly off due to approximation, but molality is direct.

Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Vapour Pressure and Raoult's Law - Ideal and Non-ideal Solutions

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Solubility - of Solids and Gases in Liquids Henry's Law

A gas has a partial pressure of 5 bar and a Henry’s law constant of 500 bar. What is the mole fraction in the solution?

p = KH · x . x = (5/500) = 0.01 .

Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Solubility - of Solids and Gases in Liquids Henry's Law

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Solubility - of Solids and Gases in Liquids Henry's Law

The solubility of a gas in water follows Henry’s law with a constant of 150 bar. If the gas’s partial pressure decreases

Henry’s law: p = KH · x . Initial x₁ = (6/150) = 0.04 , final x₂ = (3/150) = 0.02 . Factor = (x₂/x₁) = (0.02/0.04) = 0.5 (decreases by a factor of 2).

Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Solubility - of Solids and Gases in Liquids Henry's Law

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Solubility - of Solids and Gases in Liquids Henry's Law

A gas has a Henry’s law constant of 50 bar. If its mole fraction in a solution is 0.04, what is its partial pressure abo

Henry’s law: p = KH · x . p = 50 × 0.04 = 2 bar .

Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Solubility - of Solids and Gases in Liquids Henry's Law

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Solubility - of Solids and Gases in Liquids Henry's Law

A gas has a Henry’s law constant of 250 bar. If its mole fraction in a solution is 0.008, what is its partial pressure?

Henry’s law: p = KH · x . p = 250 × 0.008 = 2 bar .

Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Solubility - of Solids and Gases in Liquids Henry's Law

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Solubility - of Solids and Gases in Liquids Henry's Law

A gas has a Henry’s law constant of 120 bar. If its mole fraction in a solution is 0.025, what is its partial pressure?

Henry’s law: p = KH · x . p = 120 × 0.025 = 3 bar .

Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Solubility - of Solids and Gases in Liquids Henry's Law

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Colligative Properties - Osmotic Pressure and Reverse Osmosis

A gas has a Henry’s law constant of 300 bar. If its partial pressure is 6 bar, what is the mole fraction in the solution

p = KH · x . x = (6/300) = 0.02 .

Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Colligative Properties - Osmotic Pressure and Reverse Osmosis

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Colligative Properties - Osmotic Pressure and Reverse Osmosis

A gas has a Henry’s law constant of 200 bar. If its partial pressure is 4 bar, what is the mole fraction in the solution

p = KH · x . x = (4/200) = 0.02 .

Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Colligative Properties - Osmotic Pressure and Reverse Osmosis

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Abnormal Molar Masses and van't Hoff Factor

A solution of a gas in water has a mole fraction of 0.02 at 5 bar pressure. If the Henry’s law constant decreases by 20%

Initial: 5 = KH · 0.02 , KH = 250 bar . New KH = 250 × 0.8 = 200 bar . New p = 200 × 0.02 = 4 bar .

Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Abnormal Molar Masses and van't Hoff Factor

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Chemical Equilibrium - Law of Mass Action and Equilibrium Constant

For CO₂(g) CO₂(aq) , the equilibrium is governed by which law?

The solubility of a gas in a liquid is proportional to its pressure above the liquid, as stated by Henry's Law.

Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Chemical Equilibrium - Law of Mass Action and Equilibrium Constant

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Chemical Equilibrium - Law of Mass Action and Equilibrium Constant

Which law relates the partial pressure of a gas to its solubility in a liquid?

Henry’s Law states that the solubility of a gas in a liquid is directly proportional to its partial pressure above the liquid.

Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Chemical Equilibrium - Law of Mass Action and Equilibrium Constant

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