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#Henry's law

27 public questions tagged with this topic.

CHEMISTRY

The Henry's law constant for a gas in water is 8 × __10POW₃__bar at 298 K. What is the mole fraction of the gas under

Given: The Henry's law constant for a gas in water is 8 × __10POW₃__bar at 298 K. What is the mole fraction of the gas under a partial pressure of 0.4 bar? These values define the system as per NCERT data. Formula: p = K_H · x. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: 0.4 = 8 × __10POW₃__ · x . x = 0.4/8 × __10POW₃__= 5 × 10⁻⁵. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom and Periodicity, Topic: Mole concept, atomic models and periodic trends.

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CHEMISTRY

A gas dissolves in water with a solubility of 0.005 mol/L at a partial pressure of 0.5 bar at 298 K. What is the Henry's

Given: A gas dissolves in water with a solubility of 0.005 mol/L at a partial pressure of 0.5 bar at 298 K. What is the Henry's law constant ( K_H ) in bar? These values define the system as per NCERT data. Formula: Henry's law: p = K_H · solubility (in molarity). This is the standard NCERT relation for this phenomenon. Substitution & Calculation: K_H = fracpsolubility = 0.5/0.005 = 100 bar . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Relevant Chemistry topic covering principles and examples as per NCERT.

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