Practice question
Question
A gas dissolves in water with a solubility of 0.005 mol/L at a partial pressure of 0.5 bar at 298 K. What is the Henry's law constant ( K_H ) in bar?
Explanation
Given:
A gas dissolves in water with a solubility of 0.005 mol/L at a partial pressure of 0.5 bar at 298 K. What is the Henry's law constant ( K_H ) in bar?
These values define the system as per NCERT data.
Formula:
Henry's law: p = K_H · solubility (in molarity).
This is the standard NCERT relation for this phenomenon.
Substitution & Calculation:
K_H = fracpsolubility = 0.5/0.005 = 100 bar .
Result:
The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
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