5 public questions tagged with this topic.
Elimination (E₂) of CH₃CH₂CHBrCH₂CH₂CH₃ with alcoholic KOH forms CH₃CH₂CH=CHCH₂CH₃ (3-hexene) per Zaitsev's rule.
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Polyhalogen Compounds - Chloroform Iodoform DDT Freons
CH₃CH₂CH₂CH₂CH₂I reacts with excess NH₃ via SN₂ to form CH₃CH₂CH₂CH₂CH₂NH₂ (pentylamine) after heating.
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Elimination Reactions and Reaction with Metals and Other Reactions
This is a Wurtz reaction, coupling two CH₃CH₂CH₂CH₂I molecules to form CH₃CH₂CH₂CH₂CH₂CH₂CH₂CH₃ (octane).
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Elimination Reactions and Reaction with Metals and Other Reactions
Alcoholic KOH promotes elimination (E₂) in (CH₃)2CHCH₂Br , forming (CH₃)2C=CH₂ (2-methylpropene).
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Elimination Reactions and Reaction with Metals and Other Reactions
Alcoholic KOH promotes elimination (E₂) in CH₃CH₂CH₂CHBrCH₃ , forming CH₃CH₂CH=CHCH₃ (2-pentene) per Zaitsev's rule.
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Elimination Reactions and Reaction with Metals and Other Reactions
