Practice question
Question
Which halide yields CH₃CH₂CH=CHCH₂CH₃ as the major product with alcoholic KOH at 80°C?
Explanation
Elimination (E₂) of CH₃CH₂CHBrCH₂CH₂CH₃ with alcoholic KOH forms CH₃CH₂CH=CHCH₂CH₃ (3-hexene) per Zaitsev's rule.
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