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Δ H = Δ U + Δ ng RT. Here, Δ ng = 2 - 3 = -1, RT = 8.314 × 298 × 10⁻³ = 2.48 kJ, so Δ H = Δ U - 2.48 kJ.
Ref: NCERT Class 11 Chemistry > Chapter 5: Thermodynamics > Topic: Third Law of Thermodynamics and Applications
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