#dehydrohalogenation

2 public questions tagged with this topic.

Dehydrohalogenation of 2-bromopropane with alcoholic KOH follows Zaitsev's rule, forming the more substituted alkene, CH₃CH=CH₂ (propene).

Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Polyhalogen Compounds - Chloroform Iodoform DDT Freons

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Elimination (E₂) of (CH₃)2CHCH₂CH₂Br with alcoholic KOH forms (CH₃)2C=CHCH₃ (2-methyl-2-butene) per Zaitsev's rule.

Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Elimination Reactions and Reaction with Metals and Other Reactions

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