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Question

What is the product when (CH₃)2CHCH₂CH₂Br reacts with alcoholic KOH at low temperature?

Options

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Explanation

Elimination (E₂) of (CH₃)2CHCH₂CH₂Br with alcoholic KOH forms (CH₃)2C=CHCH₃ (2-methyl-2-butene) per Zaitsev's rule.