Practice question
Question
What is the product when (CH₃)2CHCH₂CH₂Br reacts with alcoholic KOH at low temperature?
Explanation
Elimination (E₂) of (CH₃)2CHCH₂CH₂Br with alcoholic KOH forms (CH₃)2C=CHCH₃ (2-methyl-2-butene) per Zaitsev's rule.
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