#conductivity calculation

Electrochemical Cells - Galvanic Cells and Electrode Potential

A weak electrolyte has Lambdam° = 390 S cm² mol⁻¹ and a degree of dissociation of 0.02 at 0.1 M. What is the conductivit

Lambdam = α Lambdam° = 0.02 × 390 = 7.8 S cm² mol⁻¹ . kappa = (Lambdam × c/1000) = (7.8 × 0.1/1000) = 0.00078 S cm⁻¹ .

Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Electrochemical Cells - Galvanic Cells and Electrode Potential

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Conductance - Conductivity Molar Conductivity and Kohlrausch Law

A conductivity cell with cell constant 0.6 cm⁻¹ shows a resistance of 200 Ω with a 0.03 M KCl solution. What is the mola

kappa = (cell constant/R) = (0.6/200) = 0.003 S cm⁻¹ . Lambdam = (kappa × 1000/c) = (0.003 × 1000/0.03) = 100 S cm² mol⁻¹ .

Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Conductance - Conductivity Molar Conductivity and Kohlrausch Law

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Conductance - Conductivity Molar Conductivity and Kohlrausch Law

A conductivity cell with cell constant 0.6 cm⁻¹ shows a resistance of 200 Ω with a 0.03 M KCl solution. What is the mola

kappa = (cell constant/R) = (0.6/200) = 0.003 S cm⁻¹ . Lambdam = (kappa × 1000/c) = (0.003 × 1000/0.03) = 100 S cm² mol⁻¹ .

Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Conductance - Conductivity Molar Conductivity and Kohlrausch Law

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Conductance - Conductivity Molar Conductivity and Kohlrausch Law

The conductivity of a 0.015 M solution is 0.00195 S cm⁻¹. What is its molar conductivity?

Lambdam = (kappa × 1000/c) = (0.00195 × 1000/0.015) = 130 S cm² mol⁻¹ .

Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Conductance - Conductivity Molar Conductivity and Kohlrausch Law

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Conductance - Conductivity Molar Conductivity and Kohlrausch Law

The conductivity of a 0.015 M solution is 0.00195 S cm⁻¹. What is its molar conductivity?

Lambdam = (kappa × 1000/c) = (0.00195 × 1000/0.015) = 130 S cm² mol⁻¹ .

Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Conductance - Conductivity Molar Conductivity and Kohlrausch Law

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Conductance - Conductivity Molar Conductivity and Kohlrausch Law

The dissociation constant of acetic acid is 1.78 × 10⁻⁵ mol L⁻¹ at 0.001 M concentration with molar conductivity 48.15 S

α = sqrt(Ka/c) = sqrt(1.78 × 10⁻⁵/0.001) = 0.133 . α = (Lambdam/Lambdam°) , 0.133 = (48.15/Lambdam°) , Lambdam° = 390.5 S cm² mol⁻¹ .

Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Conductance - Conductivity Molar Conductivity and Kohlrausch Law

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Conductance - Conductivity Molar Conductivity and Kohlrausch Law

The degree of dissociation of a weak acid is 0.02, and its molar conductivity at infinite dilution is 400 S cm² mol⁻¹. W

α = (Lambdam/Lambdam°) , 0.02 = (Lambdam/400) , Lambdam = 8 S cm² mol⁻¹ .

Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Conductance - Conductivity Molar Conductivity and Kohlrausch Law

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Conductance - Conductivity Molar Conductivity and Kohlrausch Law

The degree of dissociation of a weak acid is 0.02, and its molar conductivity at infinite dilution is 400 S cm² mol⁻¹. W

α = (Lambdam/Lambdam°) , 0.02 = (Lambdam/400) , Lambdam = 8 S cm² mol⁻¹ .

Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Conductance - Conductivity Molar Conductivity and Kohlrausch Law

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Conductance - Conductivity Molar Conductivity and Kohlrausch Law

The conductivity of a 0.002 M weak electrolyte solution is 8 × 10⁻⁵ S cm⁻¹. What is its molar conductivity?

Lambdam = (kappa × 1000/c) = (8 × 10⁻⁵ × 1000/0.002) = 40 S cm² mol⁻¹ .

Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Conductance - Conductivity Molar Conductivity and Kohlrausch Law

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Conductance - Conductivity Molar Conductivity and Kohlrausch Law

The conductivity of a 0.002 M weak electrolyte solution is 8 × 10⁻⁵ S cm⁻¹. What is its molar conductivity?

Lambdam = (kappa × 1000/c) = (8 × 10⁻⁵ × 1000/0.002) = 40 S cm² mol⁻¹ .

Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Conductance - Conductivity Molar Conductivity and Kohlrausch Law

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Conductance - Conductivity Molar Conductivity and Kohlrausch Law

The conductivity of a 0.005 M KBr solution is 0.00072 S cm⁻¹. What is the molar conductivity?

Lambdam = (kappa × 1000/c) = (0.00072 × 1000/0.005) = 144 S cm² mol⁻¹ .

Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Conductance - Conductivity Molar Conductivity and Kohlrausch Law

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Conductance - Conductivity Molar Conductivity and Kohlrausch Law

The conductivity of a 0.005 M KBr solution is 0.00072 S cm⁻¹. What is the molar conductivity?

Lambdam = (kappa × 1000/c) = (0.00072 × 1000/0.005) = 144 S cm² mol⁻¹ .

Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Conductance - Conductivity Molar Conductivity and Kohlrausch Law

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