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A weak electrolyte has Lambdam° = 390 S cm² mol⁻¹ and a degree of dissociation of 0.02 at 0.1 M. What is the conductivity of the solution?

Choose one · Correct answer highlighted

0.0078 S cm⁻¹ 0.00078 S cm⁻¹ Correct 0.039 S cm⁻¹ 0.00039 S cm⁻¹

Lambdam = α Lambdam° = 0.02 × 390 = 7.8 S cm² mol⁻¹ . kappa = (Lambdam × c/1000) = (7.8 × 0.1/1000) = 0.00078 S cm⁻¹ .

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