30 public questions tagged with this topic.
For a strong electrolyte, α = (Lambdam/Lambdam°) , but here it’s less than 1 due to ion interaction. α = (228/240) = 0.95 .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Variation of Conductivity with Concentration and Measurement
α = (Lambdam/Lambdam°) = (46/404) = 0.114 .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Variation of Conductivity with Concentration and Measurement
Lambdam = α Lambdam° = 0.02 × 390 = 7.8 S cm² mol⁻¹ . kappa = (Lambdam × c/1000) = (7.8 × 0.1/1000) = 0.00078 S cm⁻¹ .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Electrochemical Cells - Galvanic Cells and Electrode Potential
α = (Lambdam/Lambdam°) , 0.05 = (19/Lambdam°) , Lambdam° = 380 S cm² mol⁻¹ .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Corrosion and Applications of Electrochemistry
α = (Lambdam/Lambdam°) , 0.02 = (Lambdam/400) , Lambdam = 8 S cm² mol⁻¹ .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Conductance - Conductivity Molar Conductivity and Kohlrausch Law
α = (Lambdam/Lambdam°) , 0.02 = (Lambdam/400) , Lambdam = 8 S cm² mol⁻¹ .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Conductance - Conductivity Molar Conductivity and Kohlrausch Law
α = (Lambdam/Lambdam°) , 0.25 = (95/Lambdam°) , Lambdam° = 380 S cm² mol⁻¹ .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Conductance - Conductivity Molar Conductivity and Kohlrausch Law
α = (Lambdam/Lambdam°) , 0.1 = (Lambdam/380) , Lambdam = 38 S cm² mol⁻¹ .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Conductance - Conductivity Molar Conductivity and Kohlrausch Law
α = (Lambdam/Lambdam°) , 0.1 = (Lambdam/380) , Lambdam = 38 S cm² mol⁻¹ .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Conductance - Conductivity Molar Conductivity and Kohlrausch Law
Δ Tb = i · Kb · m . 0.26 = i × 0.52 × 0.25 . i = (0.26/0.52 × 0.25) = 2 . i = 1 + α (n - 1) , 2 = 1 + α (2 - 1) , α = 1 .
Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Colligative Properties - Relative Lowering and Elevation of Boiling Point
Δ Tb = i · Kb · m . 0.156 = i × 0.52 × 0.1 . i = (0.156/0.52 × 0.1) = 3 . i = 1 + α (n - 1) , 3 = 1 + α (3 - 1) , 2α = 2 , α = 1 .
Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Colligative Properties - Relative Lowering and Elevation of Boiling Point
Pi = i · M · RT . 1.845 = i × 0.25 × 0.0821 × 300 . i = (1.845/0.25 × 24.63) ≈ 0.3 × 6 = 1.8 . i = 1 + α , 1.8 = 1 + α , α = 0.8 .
Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Colligative Properties - Osmotic Pressure and Reverse Osmosis
