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#chlorine percentage

3 public questions tagged with this topic.

Qualitative and Quantitative Analysis - Lassaigne Test and Estimation

In the Carius method, 0.2 g of an organic compound gave 0.235 g of AgCl. What is the percentage of chlorine?

Molar mass of AgCl = 143.5 g/mol, Cl = 35.5 g/mol. Mass of Cl = (35.5/143.5) × 0.235 = 0.058 g. Percentage = (0.058/0.2) × 100 = 29%.

Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Qualitative and Quantitative Analysis - Lassaigne Test and Estimation

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Qualitative and Quantitative Analysis - Lassaigne Test and Estimation

In the Carius method, 0.18 g of a compound gave 0.287 g of AgCl. What is the percentage of chlorine?

Molar mass of AgCl = 143.5 g/mol, Cl = 35.5 g/mol. Mass of Cl = (35.5/143.5) × 0.287 = 0.071 g. Percentage = (0.071/0.18) × 100 ≈ 39.44% ≈ 40%.

Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Qualitative and Quantitative Analysis - Lassaigne Test and Estimation

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Qualitative and Quantitative Analysis - Lassaigne Test and Estimation

In the Carius method, 0.15 g of a compound gave 0.287 g of AgCl. If the same sample in Kjeldahl’s method neutralized 10

Mass of Cl = (35.5/143.5) × 0.287 = 0.071 g. Percentage = (0.071/0.15) × 100 = 47.33% ≈ 47%. Kjeldahl’s data is for nitrogen, irrelevant here.

Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Qualitative and Quantitative Analysis - Lassaigne Test and Estimation

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